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If bodies at the equator of the earth are to be weightless, what should be its time period of rotation ? |
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Answer» SOLUTION :The ACCELERATION due to gravity at LATITUDE `phi` is ` g_phi = g - R omega^2 cos^2 phi` For bodies to be weightless at equator then `g_phi` must be zero.`rArr 0 = g - R omega^2 [ because phi = 0^@]` ` rArr omega^2 = g/R rArr omega = sqrt(g/R) , ` But we know that , `omega = (2pi)/(T) , THEREFORE T = 2pi sqrt(R/g)` |
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