if both x-2 and x-1/2 are factors of px²+qx+r show that p=r

1.	if both x-2 and x-1/2 are factors of px²+qx+r show that p=r
Answer» x-2=0x=2g(x)=px²+qx+rg(2)=p(2)²+q(2)+r=4p+2q+r=0x-1/2=0x=1/2g(1/2)=p(1/2)²+q(1/2)+r=p/4+q/2+r=0 =4(p/4+q/2+r)=0x4 =p+2q+4r=0p+2q+4r=4p+2q+r4r-r=4p-p3r=3pr=0

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