If both x − 2 and x-12 are factors of px2 + 5x + r, then(a) p = r(b) p + r = 0(c) 2p + r = 0(d) p + 2r = 0

If both x − 2 and x-12 are factors of px2 + 5x + r, then(a) p = r(b)

1.	If both x − 2 and x-12 are factors of px2 + 5x + r, then(a) p = r(b) p + r = 0(c) 2p + r = 0(d) p + 2r = 0
Answer» If both x − 2 and $x - \frac{1}{2}$ are factors of px² + 5x + r, then (a) p = r (b) p + r = 0 (c) 2p + r = 0 (d) p + 2r = 0