If c > a; show that cba – abc = 99(c – a).

1.	If c > a; show that cba – abc = 99(c – a).
Answer» Given : c > a To show : cba – abc = 99(c – a) Proof: cba = 100c + 106 + a ……….(i) (By using property 3) abc = 100a + 106 + c ………(ii) (By using property 3) Subtracting (ii) from (i) cba – abc= 100c+ 106 + a- 100a- 106-c => cba – abc = 99c – 99a => cba – abc = 99(c – a) Hence proved.

Answer»

Given : c > a

To show : cba – abc = 99(c – a)

Proof:

cba = 100c + 106 + a ……….(i)

(By using property 3)

abc = 100a + 106 + c ………(ii)

(By using property 3)

Subtracting (ii) from (i)

cba – abc= 100c+ 106 + a- 100a- 106-c

=> cba – abc = 99c – 99a

=> cba – abc = 99(c – a)

Hence proved.

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