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If C is capacitance, Vis potential, rho is specific resistance and epsilon_(0) is permittivity of free space, then the dimensions of (CV)/(rhoepsilon_(0))are same as that of |
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Answer» charge `[RHO]= [ML^(3)T^(-3)A^(-2)], [epsilon_(0)]= [M^(-1)L^(-3)T^(4)A^(2)]` `:.[(CV)/(rhoepsilon_(0))]= ([C][V])/([rho][epsilon_(0)])= ([M^(-1)L^(-2)T^(4)A^(2)][ML^(2)T^(-3)A^(-1)])/([ML^(3)T^(-3)A^(-2)][M^(-1)L^(-3)T^(4)A^(2)])= ([AT])/([T])= [A]= ["Current"]` |
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