1.

If C_(r)= ""^(n)C_(r), then C_(0)+C_(4)+C_(8)+C_(12)+cdots=

Answer»

`(2^((n)/(2))[SIN""(NPI)/(4)+2^(n/(2)-1)]]/(2)`
`2^(n/(2))sin""(npi)/(2)`
`2^(n-1)COS""(npi)/(4)`
`(2^(n/(2))[cos ""(npi)/(4)+2^(n/2-1)])/(2)`

Answer :A


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