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If `CO_(2)` gas is passed through 500 ml of `0.5 (M) Ca(OH)_(2)`, the amount of `CaCO_(3)` produced isA. 10 gB. 20 gC. 50 gD. 25 g |
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Answer» Correct Answer - D By equating the equivalents `W/100xx2=(500xx0.5xx2)/1000` `W=25 g" "(W="mass of "CaCO_(3))` |
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