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If co-ordinates ofa moving point at time t are given by x=a (l+sint) and y=a(1-cost), then: |
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Answer» the slope of accelration time GRAPH is zero `v=sqrt(((dx)/(dt))^(2)+((dy)/(dt))^(2))` `a=sqrt(((d^(2)x)/(dt^(2)))^(2)+((d^(2)y)/(dt^(2)))^(2))` |
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