If concentration of OH^(-) ions in the reaction Fe (OH)_(3) (s) hArr Fe^(3+) (aq) + 3 OH^(-) (aq) is decreased by 1/4 times, then equilibrium concentration of Fe^(3+) will increase by

If concentration of OH^(-) ions in the reaction Fe (OH)_(3) (s) hArr

1.	If concentration of OH^(-) ions in the reaction Fe (OH)_(3) (s) hArr Fe^(3+) (aq) + 3 OH^(-) (aq) is decreased by 1/4 times, then equilibrium concentration of Fe^(3+) will increase by
Answer» 8 times 16 times 64 times 4 times Solution :`K= ([Fe^(3+)][OH^(-)]^(3))/([Fe (OH)_(3)(s)])=[Fe^(3+)] [OH^(-)]^(3)=xy^(3)(say)` If `[OH^(-)]` is decreased to y/4, to keep K CONSTANT ` x'(y/4)^(3)= x +y ^(3):. x' = 64 x `