1.

If cos alpha+2cos beta+3cos gamma=sinalpha+2sinbeta+3singamma=0 then sin 3alpha+8sin3 beta+27sin 3gamma=

Answer»

`18COS(alpha+beta+gamma)`
`18sin(alpha+beta+gamma)`
`SIN(alpha+beta+gamma)`
`COS(alpha+beta+gamma)`

ANSWER :B


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