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If (cosθ+isinθ)(cos2θ+isin2θ)⋯(cosnθ+isinnθ)=1, where θ=kmπn2+1 for m∈Z, then the value of k is |
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Answer» If (cosθ+isinθ)(cos2θ+isin2θ)⋯(cosnθ+isinnθ)=1, where θ=kmπn2+1 for m∈Z, then the value of k is |
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