1.

If (cosx-cosalpha)/(cosx-cosbeta)=(sin^(2)alphacosbeta)/(sin^(2)betacosalpha), then

Answer»

`cosx=(cosalpha+cosbeta)/(1+cosalphacosbeta)`
`cosx=(cosalpha+cosbeta)/(1-cosalphacosbeta)`
`"TAN"(x)/(2)="tan"(alpha)/(2)"tan"(beta)/(2)`
`"tan"(x)/(2)=-"tan"(alpha)/(2)"tan"(beta)/(2)`

ANSWER :A::C::D


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