If cot−1(4+24)+cot−1(4+64)+cot−1(4+124)+.....∞=tan−1(ab), wh – InterviewSolution

1.	If cot−1(4+24)+cot−1(4+64)+cot−1(4+124)+.....∞=tan−1(ab), where a and b are relatively prime, then
Answer» If $c o t^{- 1} (4 + \frac{2}{4}) + c o t^{- 1} (4 + \frac{6}{4}) + c o t^{- 1} (4 + \frac{12}{4}) + . . . . . \infty = t a n^{- 1} (\frac{a}{b}),$ where a and b are relatively prime, then

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