1.

If Cr stands for nCr then the sum of the series 2(n2)!(n2)n![C20−2C21+3C22−⋯+(−1)n(n+1)C2n], where n is an even positive integer is equal to

Answer»

If Cr stands for nCr then the sum of the series
2(n2)!(n2)n![C202C21+3C22+(1)n(n+1)C2n], where n is an even positive integer is equal to



Discussion

No Comment Found