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If d is the Highest Common Factor of 32 and 60, find x and y satisfying d = 32x + 60y. |
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Answer» Applying Euclid’s divison lemma to 32 and 60, we get 60 = 32 x 1 + 28 … (i) The remainder is 28 ≠ 0. Again applying division lemma 32 = 28 x 1 + 4 … (ii) The remainder 4 ≠ 0. Again applying division lemma 28 = 4 x 7 + 0 … (iii) The remainder zero. ∴ H.C.F. of 32 and 60 is 4. From (ii), we get 32 = 28 x 1 + 4 ⇒ 4 = 32 – 28 x 1 ⇒ 4 = 32 – (60 – 32 x 1) x 1 ⇒ 4 = 32 – 60 + 32 ⇒ 4 = 32 x 2 + (-1) x 60 ∴ x = 2 and y = -1 |
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