If Δ1=∣∣∣∣a1b1c1a2b2c2a3b3c3∣∣∣∣ and Δ2=∣∣∣∣ – InterviewSolution

1.	If Δ1=∣∣∣∣a1b1c1a2b2c2a3b3c3∣∣∣∣ and Δ2=∣∣∣∣a1+pb1b1+qc1c1+ra1a2+pb2b2+qc2c2+ra2a3+pb3b3+qc3c3+ra3∣∣∣∣ are such that Δ2=k⋅Δ1, then k is
Answer» If $Δ_{1} = ∣ ∣∣ ∣ \begin{matrix} a_{1} & b_{1} & c_{1} a_{2} & b_{2} & c_{2} a_{3} & b_{3} & c_{3} \end{matrix} ∣ ∣∣ ∣$ and $Δ_{2} = ∣ ∣∣ ∣ \begin{matrix} a_{1} + p b_{1} & b_{1} + q c_{1} & c_{1} + r a_{1} a_{2} + p b_{2} & b_{2} + q c_{2} & c_{2} + r a_{2} a_{3} + p b_{3} & b_{3} + q c_{3} & c_{3} + r a_{3} \end{matrix} ∣ ∣∣ ∣$ are such that $Δ_{2} = k \cdot Δ_{1},$ then $k$ is

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