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If ΔABC ~ ΔDEF, ∠A = 50°, then ∠E + ∠F = ……………… (A) 100° (B) 125° (C) 130° (D) 140° |
Answer» Correct option is (C) 130° Given that \( \triangle ABC \sim \triangle DEF\) \(\therefore\) \(\angle D=\angle A=50^\circ\) (Given \(\angle A=50^\circ)\) In \(\triangle DEF,\) \(\angle D+\angle E+\angle F=180^\circ\) (Sum of angles in a triangle) \(\Rightarrow\) \(\angle E+\angle F=180^\circ-\angle D\) \(=180^\circ-50^\circ=130^\circ\) Correct option is: (C) 130° |
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