If Delta E is the energy emitted in electron vots when an electronic transition occurs from higher energy level to a lower energy level in H-atom, the wavelength of the line produced is approximately equal to

If Delta E is the energy emitted in electron vots when an electronic t

1.	If Delta E is the energy emitted in electron vots when an electronic transition occurs from higher energy level to a lower energy level in H-atom, the wavelength of the line produced is approximately equal to
Answer» `(19800)/(DeltaE) Å` `(12375)/(DeltaE) Å` `(13600)/(DELTA E) Å` `(21800)/(Delta E) Å` Solution :`Delta E = hv = (HC)/(lamda) or lamda = (hc)/(Delta E)` If `Delta E` is in joules, `lamda = ((6.6 xx 10^(-34) KG m^(2) s^(-1)) (3.0 xx 10^(8) ms^(-1)))/(Delta E (kg m^(2) s^(-1)))` `= (19.8 xx 10^(-26))/(Delta E) m` If `Delta E` is in eV, then as `1 eV = 1.6 xx 10^(-19) J` `lamda = (19.8 xx 10^(-26))/(Delta E xx 1.6 xx 10^(-19)) m = (12.375 xx 10^(-7))/(Delta E) m` `= (12375 xx 10^(-10))/(Delta E) m = (12375)/(Delta E) Å`