1.

If Delta H = 35.5 kJ/mol and Delta S = 83.6 J/mol K. At what temperature the reaction will be spontaneous?

Answer»

`T GT 425 K`
Each temperature
`T lt 298` K
`T gt 425 K`

Solution :`DELTA G = Delta H - T Delta S`
`T= (Delta H)/( Delta S) = (35.5 xx 1000)/( 83.6) = 425K`
`therefore` Reaction will be spontaneous at temperature `T gt 425 K`.


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