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| 1. |
If $\Delta \mathrm{ABC} \sim \Delta \mathrm{QRP}, \frac{\operatorname{arc}(\Delta \mathrm{ABC})}{\operatorname{ar}(\Delta \mathrm{QRP})}=\frac{9}{4},$ and $\mathrm{BC}=15 \mathrm{cm},$ then find $\mathrm{PR}$ |
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