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If `DeltaH_(f)^(@)` of `Icl(g)`, `Cl(g)` and `I(g)` is `17.57`, `121.34` and `106.96 J mol^(-1)` respectively. Then bond dissociation energy of `I-Cl` bond isA. 17.57B. 210.73C. 35.15D. 106.96 |
Answer» Correct Answer - B The process will be: `I(g)+Cl(g)toI-Cl(g)," "DeltaH^(@)=17.57" J "mol^(-1)` `DeltaH=`Heats of atomisation of I(g) and Cl(g)`-`Bond energy of I-Cl bond `17.57=121.34+106.96-x` `x=210.73" J "mol^(-1)` |
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