If density of CH³OH is 0.80 kg/L find its volume to prepare 2.5l of 0.25M aqueous solution is

If density of CH³OH is 0.80 kg/L find its volume to prepare 2.5l of 0

1.	If density of CH³OH is 0.80 kg/L find its volume to prepare 2.5l of 0.25M aqueous solution is
Answer» MASS of CH3OH required isM=Volume of solution × Molariy of solution×Molar mass of methanol=2.5×0.25×32=20 g.Volume of CH3OH needed = mass/density=20/0.80=25mlhope this HELPS u...