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If diagonal of a parallelogram bisects one of the angles of theparallelogram, it also bisects the second angle. Also, prove that it is arhombus. |
Answer» Given- AC diagonal bisects `/_A` AB||CD and AC is transverse `/_3=/_1-(1)` AD||BC and AC is transverse `/_2=/_4-(2)` AC bisects`/_A` `/_1=/_2-(3)` `/_3=/_4` AC bisects `/_A` `/_1=/_4` AB=DC and BC=AB AB=BC-CD=CD ABCD is a rhombus. |
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