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Two opposite angles of a parallelogram are (3x-2)°and (50-x)°.Find the measure of each angle of the parallelogram. |
Answer» Given, Two opposite angles of a parallelogram (3x - 2) and (50 – x) Opposite angles of a parallelogram are equal, 3x – 2 = 50 – x 4x = 52 ∘ x = 13 ∘ So, angles are 3x – 2 = 3×13-2 = 37∘ 50 – x = 50 -13 = 37∘ Sum of other two angles = 360 - 2×37 = 360 – 74 = 286∘ So each angle will be = \(\frac{286}{2}\) = 143∘ |
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