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if displacement of a body is equal to 200 + - 5 and time taken by it equal to 220 plus minus 0.2 seconds then find the percentage error in the calculation of velocity with its calculation |
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Answer» Given,S = 200 +/- 5T = 20 +/- 0.2We know that, V = s/t∆V/V% = (∆5/5 + ∆t/t)100 =(5/200 + 0.2/20)100 |
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