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If displacement of a body s = (200 ± 5) m and time taken by it t = (20 + 0.2) s, then find the percentage error in the calculation of velocity. |
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Answer» percentage error in measurement of displacement = \(\frac{5}{200}\)x100 Percentage error in measurement of time = \(\frac{0.2}{20}\) x 100 ∴ Maximum permissible error = 2.5 + 1 = 3.5% |
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