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If displacement of a body s = (200 pm 5) m and time taken by it t = (20 pm 0.2) s, then find the percentage error in the calculation of velocity. |
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Answer» Solution :Percentage error in MEASUREMENT of DISPLACEMENT `= (5)/(200) xx 100` Percentage error in measurement of time `= (0.2)/(20) xx 100` `:.` MAXIMUM permissible error `= 2.5 + 1 = 3.5%` |
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