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If dissociation constant of ammonia is `10^(-5)`, its `pK_(b)` and `pK_(4)` value respectively areA. 5 and 9B. 9 and 5C. 7 and 7D. 4 and 10 |
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Answer» Correct Answer - A `K_(b)` of `NH_(3)` is `10^(-5)` (given) `:. pK_(b) = 5` and `pK_(a) = 14 - 5 = 9` Hence, `pK_(b)` and `pK_(a)` values are 5 and 9 respectively. |
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