1.

If dissociation for reaction PCl_(5) hArr PCl_(3) + Cl_(2) is 20% at 1 atm pressue . Calculate the value of K_(C).

Answer»

`0.04`
`0.05`
`0.07`
`0.06`

SOLUTION :`K_(C) = ([PCl_(3)][Cl_(2)])/([PCl_(5)]) = ([(20)/(100)] xx [(20)/(100)])/([(80)/(100)]) = (0.2 xx 0.2 )/(0.8) = (0.04)/(0.8) = 0.05`


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