If distance = 5000mthen by a*10^b 5 * 10^3 a=5 – InterviewSolution

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1.	If distance = 5000mthen by a10^b 5 10^3 a=5 ("a" not < or > 5 but = 5) then magnitude of order is 3 or 4
Answer» If distance = 5000m then by a10^b 5 10^3 a=5 ("a" not < or > 5 but = 5) then magnitude of order is 3 or 4

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