If distance between two molecules of gases becomes half then which type of changes occurs in London forces ?

If distance between two molecules of gases becomes half then which typ

1.	If distance between two molecules of gases becomes half then which type of changes occurs in London forces ?
Answer» Solution :London FORCES `prop (1)/(r^(6))= k (1)/(r^(6))` Initially London force `= x_(1)=k(1)/(r^(6))` Initial distasnce = r FINAL distance `= (r )/(2)` Final london force `x_(2)=k(1)/(((r )/(2))^(6))=k(2^(6))/(r^(6))` `(x_(2))/(x_(1))=((k.2^(6))/(r^(6)))xx((r^(6))/(k))` `= 2^(6)=2xx2xx2xx2xx2xx2 = 64` times