1.

If ∫dθ(cos2 θ(tan2θ+sec2θ)=λtanθ+2loge|f(θ)|+C where C is constant of integration, then the ordered pair (λ,f(θ)) is equal to:

Answer»

If dθ(cos2 θ(tan2θ+sec2θ)=λtanθ+2loge|f(θ)|+C where C is constant of integration, then the ordered pair (λ,f(θ)) is equal to:



Discussion

No Comment Found