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If ∫dx(1+√x)2010=2[1α(1+√x)α−1β(1+√x)β]+c, where c is constant of integration and α,β>0, then α−β is |
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Answer» If ∫dx(1+√x)2010=2[1α(1+√x)α−1β(1+√x)β]+c, where c is constant of integration and α,β>0, then α−β is |
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