1.

If ∫dx(1+√x)2010=2[1α(1+√x)α−1β(1+√x)β]+c, where c is constant of integration and α,β>0, then α−β is

Answer»

If ∫dx(1+√x)2010=2[1α(1+√x)α−1β(1+√x)β]+c, where c is constant of integration and α,β>0, then α−β is




Discussion

No Comment Found