1.

If ∫dx(1+√x)2010=2[1α(1+√x)α−1β(1+√x)β]+c, where c is constant of integration and α,β>0, then α−β is

Answer»

If dx(1+x)2010=2[1α(1+x)α1β(1+x)β]+c, where c is constant of integration and α,β>0, then αβ is




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