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If ∫dx(x2+a2)2=1ka2{xx2+a2+1atan−1xa}+C, then the value of k is(where C is constant of integration) |
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Answer» If ∫dx(x2+a2)2=1ka2{xx2+a2+1atan−1xa}+C, then the value of k is (where C is constant of integration) |
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