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If ∫dx(x2+x+1)2=atan−1(2x+1√3)+b(2x+1x2+x+1)+C, x>0 where C is the constant of integration, then the value of 9(√3a+b) is equal to

Answer» If dx(x2+x+1)2=atan1(2x+13)+b(2x+1x2+x+1)+C, x>0 where C is the constant of integration, then the value of 9(3a+b) is equal to


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