1.

If ∫dxsinx⋅cosx(tan9x+1)=1kln∣∣∣(sinx)9(sinx)9+(cosx)9∣∣∣+C, then the value of k2+1 is:(where C is integration constant)

Answer» If dxsinxcosx(tan9x+1)=1kln(sinx)9(sinx)9+(cosx)9+C, then the value of k2+1 is:

(where C is integration constant)


Discussion

No Comment Found