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If ∫dxsinx⋅cosx(tan9x+1)=1kln∣∣∣(sinx)9(sinx)9+(cosx)9∣∣∣+C, then the value of k2+1 is:(where C is integration constant) |
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Answer» If ∫dxsinx⋅cosx(tan9x+1)=1kln∣∣∣(sinx)9(sinx)9+(cosx)9∣∣∣+C, then the value of k2+1 is: (where C is integration constant) |
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