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If `e_(1),e_(2),e_(3)" and "e_(4)` are the four elementary outcomes in a sample space and `P(e_(1))=0.1,P(e_(2))=0.5,"and "P(e_(3))=0.1,` then the probability of `e_(4)` is …… |
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Answer» `because" "P(e_(1))+P(e_(2))+P(e_(3))+P(e_(4))=1` `rArr" "0.1+0.5+0.1+P(e_(4))=1` `rArr" "0.7+P(e_(4))=1` `therefore" "P(e_(4))=0.3` |
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