1.

If E= energy, G= gravitational constant, I= impulse andM = mass, the dimension of (GIM^(2))/(E^(2)) is same as that of

Answer»

time
mass
length
force

Solution :`[E]=[ML^(2)T^(-2)], [G]= [M^(-1)L^(3)T^(-2)], [I]= [MLT^(-1)]`
`[(GIM^(2))/(E^(2))]= ([M^(-1)L^(3)T^(-2)][MLT^(-1)][M^(2)])/([ML^(2)T^(-2)]^(2))= [T]`


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