If E,F,G,H are the mid point of sides of parllelogram.show that ar(EFG

1.	If E,F,G,H are the mid point of sides of parllelogram.show that ar(EFGH)=1÷2 ar(ABCD).
Answer» Const. Draw line he, ef, fg and gh Draw the line hf parallel to ab and de Such that ab is parallel to hf is parallel to de So abfh and defh are the parallelograms Now in parallelogram abfhTrialngle efh and parallelogram abfh are on the same base and between the same parallels.So triangle efh is 1/2 of parallelogram abfh (by mid point theo.)........~1Similarly, area of triangle gfh= 1/2 area parallelogram edhf (mid point theo.)........~2Now adding eqn.1 and 2 we get,Area ofParallelogram efgh=1/2 area of parallelogram abcd

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