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If e is eccentricity of the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`(where,a`lt`b), thenA. `b^(2)=a^(2)(1-e^(2))`B. `a^(2)=b^(2)(1-e^(2))`C. `a^(2)=b^(2)(e^(2)-1)`D. `b^(2)=a^(2)(e^(2)-1)` |
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Answer» Correct Answer - B Given that, `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1 altb` We know that, `e=sqrt(1-(a^(2))/(b^(2)))rArre^(2)=((b^(2)-a^(2)))/(b^(2))` `rArr b^(2)e^(2)=b^(2)=a^(2)` `rArra^(2)=b^(2)(1-e^(2))` |
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