If e1 and e2 are the eccentricity of hyperbola x2a2−y2b2=1 and y2a2� – InterviewSolution

1.	If e1 and e2 are the eccentricity of hyperbola x2a2−y2b2=1 and y2a2−x2b2=1 , then point 1e1,1e2 lies on the circle.
Answer» If $e_{1} a n d e_{2}$ are the eccentricity of hyperbola $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$ and $\frac{y^{2}}{a^{2}} - \frac{x^{2}}{b^{2}} = 1$ , then point $\frac{1}{e_{1}}, \frac{1}{e_{2}}$ lies on the circle.

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