1.

If each diode in Fig. 14.13 has a forward bias resistance of 25Ω and infinite resistance in reverse bias, what will be the values of the current I1, I2, I3 and I4?

Answer»

I3 is zero as the diode in that branch is reverse bised. Resistance in the branch AB and EF are each (125 + 25)Ω = 150Ω.

As AB and EF are identical parallel branches, their effective resistance is 150/2=75Ω

Net resistance in the circuit = (75 + 25) Ω = 100Ω .

Current I1=5/100=0.05A.

As resistances of AB and EF are equal, and I1 = I2 + I3 + I4, I3 = 0

I2=I4=0.05/2=0.025A



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