1.

If earth contracts to half of its present radius what would be length of the day at equator?

Answer»

\(I_1= \frac{2}{5}MR^2,I_2=\frac{2}{5}M(\frac{R}{2})^2\)

or \(I_2=\frac{I_1}{4}\)

\(I_1w_1=I_2w_2\)

\(I(\frac{2π}{T_1})=\frac{1}{4}I(\frac{2π}{T_2})\)

\(T_2= \frac{T_1}{4}=\frac{24}{4}=6\, hours\)



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