1.

If electro negativity of x be 3.2 and that of y be 2.2 , the percentage ionic character of xy isA. 19.5B. 18.5C. 9.5D. 29.5

Answer» Correct Answer - A
`EN_(x) - EN_(y) = 3.2 - 2.2 = 1`.
`Delta = 1`
`[Delta =` difference of electronegativity values between x and y]
% ionic character `= 16 Delta +3.5 Delta^(2) = 19.5`


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