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If electro negativity of x be 3.2 and that of y be 2.2 , the percentage ionic character of xy isA. 19.5B. 18.5C. 9.5D. 29.5 |
Answer» Correct Answer - A `EN_(x) - EN_(y) = 3.2 - 2.2 = 1`. `Delta = 1` `[Delta =` difference of electronegativity values between x and y] % ionic character `= 16 Delta +3.5 Delta^(2) = 19.5` |
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