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If enthalpy of fusion and enthalpy of vaporization of sodium metal are 2.6 kJ mol-1 and 98.2 kJ mol-1 respectively, calculate the enthalpy of sublimation of sodium. |
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Answer» ∆fusHΘ = 2.6 kJ mol−1 ∆vapHΘ = 98.2 kJ mol−1 \(\therefore\) ΔsubHΘ = ΔfusHΘ + ΔvapHΘ = 2.6 + 98.2 = 100.8 kJ mol−1 |
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