1.

If enthalpy of fusion and enthalpy of vaporization of sodium metal are 2.6 kJ mol-1 and 98.2 kJ mol-1 respectively, calculate the enthalpy of sublimation of sodium.

Answer»

fusHΘ = 2.6 kJ mol−1

vapHΘ = 98.2 kJ mol−1

\(\therefore\) ΔsubHΘ = ΔfusHΘ + ΔvapHΘ

= 2.6 + 98.2

= 100.8 kJ mol−1



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