1.

If equation `(cos^(-1)x)^(4)-8(cos^(-1)x)^(3) + a (cos^(-1)x)^(2)+b (cos^(-1)x)+16=0` has four positive real roots, where a, b epsilon R then `[x]` = (Where [.] G.I.F.)A. `1`B. `0`C. `-1`D. `2`

Answer» Correct Answer - C
All th roots of given equation are equal therefore
`cos^(-1) x=2`
`therefore x = cos 2`
`[x]=[cos 2] =-1`


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