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If equation of the plane through the straight line x−12=y+2−3=z5 and perpendicular to the plane x−y+z+2=0 is ax−by+cz+4=0, then the value of a2+b2+c is

Answer» If equation of the plane through the straight line x12=y+23=z5 and perpendicular to the plane xy+z+2=0 is axby+cz+4=0, then the value of a2+b2+c is


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