If excess CO_(2) gas is passed in 0.205 mole Ba(OH)_(2) then give the amount of BaCO_(3)produced.

If excess CO_(2) gas is passed in 0.205 mole Ba(OH)_(2) then give the

1.	If excess CO_(2) gas is passed in 0.205 mole Ba(OH)_(2) then give the amount of BaCO_(3)produced.
Answer» 81 g 40.5 g 20.25 g 162 g Solution :`{:(Ba(OH)_(2),+,CO_(2),rarr,BaCO_(2),+,H_(2)O),("1 mole",,,,"1mole",,),("0.205 mole",,,,"0.205 mole",,):}` Molecular MASS of `BaCO_(3) = 137+12+48` `= 197 g "mole"^(-1)` Weight of `BaCO_(3) = 197 xx 0.205 = 40.385g`