If f(0)=0 and that 'f' is differentiable at x = 0, and ‘k’ is a p – InterviewSolution

1.	If f(0)=0 and that 'f' is differentiable at x = 0, and ‘k’ is a positive integer. Then limx→01x[f(x)+f(x2)+f(x3)+……+f(xk)]
Answer» If f(0)=0 and that 'f' is differentiable at x = 0, and ‘k’ is a positive integer. Then ${lim}_{x \to 0} \frac{1}{x} [f (x) + f (\frac{x}{2}) + f (\frac{x}{3}) + \dots \dots + f (\frac{x}{k})]$

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