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If F(A, B, C) = A’.B’.C’ + A’.B.C’ then find F’ using De Morgan’s Law. |
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Answer» (AB’C + ABC’) (∵x’ + y’ = x’.y’) = (AB’C’)’. (A’.B.C’)’ (∵(x’.y’) = x’ + y’) = ((A’B’)’ + (C)’. ((A’B)’ + (C’)’) = ((A’)’ + (B’)’) + C).((A’)’ + (B)’ + C) = (A + B + C).(A + B’ + C) = AA + AB’ + AC + BA + BB’ + BC + CA + CB’ + CC (∵x.x = x) = A + AB’ + C + AC + AB + B’C + BC |
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